Code should execute sequentially if run in a Jupyter notebook

- See the set up page to install Jupyter, Julia (0.6+) and all necessary libraries
- Please direct feedback to contact@quantecon.org or the discourse forum

# Modeling Career Choice¶

## Overview¶

Next we study a computational problem concerning career and job choices

The model is originally due to Derek Neal [Nea99]

This exposition draws on the presentation in [LS12], section 6.5

### Model features¶

- Career and job within career both chosen to maximize expected discounted wage flow
- Infinite horizon dynamic programming with two state variables

## Model¶

In what follows we distinguish between a career and a job, where

- a
*career*is understood to be a general field encompassing many possible jobs, and - a
*job*is understood to be a position with a particular firm

For workers, wages can be decomposed into the contribution of job and career

\(w_t = \theta_t + \epsilon_t\), where

- \(\theta_t\) is contribution of career at time \(t\)
- \(\epsilon_t\) is contribution of job at time \(t\)

At the start of time \(t\), a worker has the following options

- retain a current (career, job) pair \((\theta_t, \epsilon_t)\) — referred to hereafter as “stay put”
- retain a current career \(\theta_t\) but redraw a job \(\epsilon_t\) — referred to hereafter as “new job”
- redraw both a career \(\theta_t\) and a job \(\epsilon_t\) — referred to hereafter as “new life”

Draws of \(\theta\) and \(\epsilon\) are independent of each other and past values, with

- \(\theta_t \sim F\)
- \(\epsilon_t \sim G\)

Notice that the worker does not have the option to retain a job but redraw a career — starting a new career always requires starting a new job

A young worker aims to maximize the expected sum of discounted wages

subject to the choice restrictions specified above

Let \(V(\theta, \epsilon)\) denote the value function, which is the maximum of (1) over all feasible (career, job) policies, given the initial state \((\theta, \epsilon)\)

The value function obeys

where

Evidently \(I\), \(II\) and \(III\) correspond to “stay put”, “new job” and “new life”, respectively

### Parameterization¶

As in [LS12], section 6.5, we will focus on a discrete version of the model, parameterized as follows:

- both \(\theta\) and \(\epsilon\) take values in the set
`linspace(0, B, N)`

— an even grid of \(N\) points between \(0\) and \(B\) inclusive - \(N = 50\)
- \(B = 5\)
- \(\beta = 0.95\)

The distributions \(F\) and \(G\) are discrete distributions
generating draws from the grid points `linspace(0, B, N)`

A very useful family of discrete distributions is the Beta-binomial family, with probability mass function

Interpretation:

- draw \(q\) from a β distribution with shape parameters \((a, b)\)
- run \(n\) independent binary trials, each with success probability \(q\)
- \(p(k \,|\, n, a, b)\) is the probability of \(k\) successes in these \(n\) trials

Nice properties:

- very flexible class of distributions, including uniform, symmetric unimodal, etc.
- only three parameters

Here’s a figure showing the effect of different shape parameters when \(n=50\)

```
using PyPlot
using QuantEcon
n = 50
a_vals = [0.5, 1, 100]
b_vals = [0.5, 1, 100]
fig, ax = plt[:subplots](figsize=(8, 5))
for (a, b) in zip(a_vals, b_vals)
ab_label = latexstring("a = $a, b = $b")
ax[:plot](0:n, pdf(BetaBinomial(n, a, b)), "-o", label=ab_label)
end
ax[:legend]()
```

## Implementation: `career.jl`

¶

The code for solving the DP problem described above is found in this file, which is repeated here for convenience

```
using Distributions
"""
Career/job choice model of Derek Neal (1999)
##### Fields
- `β::AbstractFloat` : Discount factor in (0, 1)
- `N::Integer` : Number of possible realizations of both ϵ and θ
- `B::AbstractFloat` : upper bound for both ϵ and θ
- `θ::AbstractVector` : A grid of values on [0, B]
- `ϵ::AbstractVector` : A grid of values on [0, B]
- `F_probs::AbstractVector` : The pdf of each value associated with of F
- `G_probs::AbstractVector` : The pdf of each value associated with of G
- `F_mean::AbstractFloat` : The mean of the distribution F
- `G_mean::AbstractFloat` : The mean of the distribution G
"""
struct CareerWorkerProblem{TF<:AbstractFloat, TI<:Integer,
TAV<:AbstractVector{TF}, TAV2<:AbstractVector{TF}}
β::TF
N::TI
B::TF
θ::TAV
ϵ::TAV
F_probs::TAV2
G_probs::TAV2
F_mean::TF
G_mean::TF
end
"""
Constructor with default values for `CareerWorkerProblem`
##### Arguments
- `β::Real(0.95)` : Discount factor in (0, 1)
- `B::Real(5.0)` : upper bound for both ϵ and θ
- `N::Real(50)` : Number of possible realizations of both ϵ and θ
- `F_a::Real(1), F_b::Real(1)` : Parameters of the distribution F
- `G_a::Real(1), G_b::Real(1)` : Parameters of the distribution F
##### Notes
There is also a version of this function that accepts keyword arguments for
each parameter
"""
# use key word argument
function CareerWorkerProblem{TF<:AbstractFloat}(;
β::TF=0.95, B::TF=5.0, N::Integer=50,
F_a::TF=1.0, F_b::TF=1.0, G_a::TF=1.0,
G_b::TF=1.0)
θ = linspace(0, B, N)
ϵ = copy(θ)
F_probs = pdf(BetaBinomial(N-1, F_a, F_b))
G_probs = pdf(BetaBinomial(N-1, G_a, G_b))
F_mean = sum(θ .* F_probs)
G_mean = sum(ϵ .* G_probs)
CareerWorkerProblem(β, N, B, θ, ϵ, F_probs, G_probs,
F_mean, G_mean)
end
"""
Apply the Bellman operator for a given model and initial value.
##### Arguments
- `cp::CareerWorkerProblem` : Instance of `CareerWorkerProblem`
- `v::Matrix`: Current guess for the value function
- `out::Matrix` : Storage for output
- `;ret_policy::Bool(false)`: Toggles return of value or policy functions
##### Returns
None, `out` is updated in place. If `ret_policy == true` out is filled with the
policy function, otherwise the value function is stored in `out`.
"""
function update_bellman!(cp::CareerWorkerProblem, v::Array, out::Array;
ret_policy::Bool=false)
# new life. This is a function of the distribution parameters and is
# always constant. No need to recompute it in the loop
v3 = (cp.G_mean + cp.F_mean + cp.β .*
cp.F_probs' * v * cp.G_probs)[1] # don't need 1 element array
for j=1:cp.N
for i=1:cp.N
# stay put
v1 = cp.θ[i] + cp.ϵ[j] + cp.β * v[i, j]
# new job
v2 = (cp.θ[i] .+ cp.G_mean .+ cp.β .*
v[i, :]'*cp.G_probs)[1] # don't need a single element array
if ret_policy
if v1 > max(v2, v3)
action = 1
elseif v2 > max(v1, v3)
action = 2
else
action = 3
end
out[i, j] = action
else
out[i, j] = max(v1, v2, v3)
end
end
end
end
function update_bellman(cp::CareerWorkerProblem, v::Array; ret_policy::Bool=false)
out = similar(v)
update_bellman!(cp, v, out, ret_policy=ret_policy)
return out
end
"""
Extract the greedy policy (policy function) of the model.
##### Arguments
- `cp::CareerWorkerProblem` : Instance of `CareerWorkerProblem`
- `v::Matrix`: Current guess for the value function
- `out::Matrix` : Storage for output
##### Returns
None, `out` is updated in place to hold the policy function
"""
function get_greedy!(cp::CareerWorkerProblem, v::Array, out::Array)
update_bellman!(cp, v, out, ret_policy=true)
end
function get_greedy(cp::CareerWorkerProblem, v::Array)
update_bellman(cp, v, ret_policy=true)
end
```

The code defines

a type

`CareerWorkerProblem`

that- encapsulates all the details of a particular parameterization
- implements the Bellman operator \(T\)

In this model, \(T\) is defined by \(Tv(\theta, \epsilon) = \max\{I, II, III\}\), where \(I\), \(II\) and \(III\) are as given in (2), replacing \(V\) with \(v\)

The default probability distributions in `CareerWorkerProblem`

correspond to discrete uniform distributions (see the Beta-binomial figure)

In fact all our default settings correspond to the version studied in [LS12], section 6.5.

Hence we can reproduce figures 6.5.1 and 6.5.2 shown there, which exhibit the value function and optimal policy respectively

Here’s the value function

```
wp = CareerWorkerProblem()
v_init = fill(100.0, wp.N, wp.N)
func(x) = update_bellman(wp, x)
v = compute_fixed_point(func, v_init, max_iter=500, verbose=false)
# === plot value function === #
tg, eg = meshgrid(wp.θ, wp.ϵ)
surf(tg,
eg,
v',
rstride=2,
cstride=2,
cmap="jet",
alpha=0.5,
linewidth=0.25)
ax = plt[:gca]()
ax[:set_zlim](150, 200)
ax[:set_xlabel]("θ")
ax[:set_ylabel]("ϵ")
ax[:view_init](ax[:elev], 225)
```

The optimal policy can be represented as follows (see Exercise 3 for code)

Interpretation:

- If both job and career are poor or mediocre, the worker will experiment with new job and new career
- If career is sufficiently good, the worker will hold it and experiment with new jobs until a sufficiently good one is found
- If both job and career are good, the worker will stay put

Notice that the worker will always hold on to a sufficiently good career, but not necessarily hold on to even the best paying job

The reason is that high lifetime wages require both variables to be large, and the worker cannot change careers without changing jobs

- Sometimes a good job must be sacrificed in order to change to a better career

## Exercises¶

### Exercise 1¶

Using the default parameterization in the type `CareerWorkerProblem`

,
generate and plot typical sample paths for \(\theta\) and \(\epsilon\)
when the worker follows the optimal policy

In particular, modulo randomness, reproduce the following figure (where the horizontal axis represents time)

Hint: To generate the draws from the distributions \(F\) and \(G\), use the type DiscreteRV

### Exercise 2¶

Let’s now consider how long it takes for the worker to settle down to a permanent job, given a starting point of \((\theta, \epsilon) = (0, 0)\)

In other words, we want to study the distribution of the random variable

Evidently, the worker’s job becomes permanent if and only if \((\theta_t, \epsilon_t)\) enters the “stay put” region of \((\theta, \epsilon)\) space

Letting \(S\) denote this region, \(T^*\) can be expressed as the first passage time to \(S\) under the optimal policy:

Collect 25,000 draws of this random variable and compute the median (which should be about 7)

Repeat the exercise with \(\beta=0.99\) and interpret the change

### Exercise 3¶

As best you can, reproduce the figure showing the optimal policy

Hint: The `get_greedy()`

method returns a representation of the optimal
policy where values 1, 2 and 3 correspond to “stay put”, “new job” and “new life” respectively. Use this and `contourf`

from `PyPlot.jl`

to produce the different shadings.

Now set `G_a = G_b = 100`

and generate a new figure with these parameters. Interpret.

## Solutions¶

### Exercise 1¶

```
wp = CareerWorkerProblem()
function solve_wp(wp::CareerWorkerProblem)
v_init = fill(100.0, wp.N, wp.N)
func(x) = update_bellman(wp, x)
v = compute_fixed_point(func, v_init, max_iter=500, verbose=false)
optimal_policy = get_greedy(wp, v)
return v, optimal_policy
end
v, optimal_policy = solve_wp(wp)
F = DiscreteRV(wp.F_probs)
G = DiscreteRV(wp.G_probs)
function gen_path(T=20)
i = j = 1
θ_ind = Int[]
ϵ_ind = Int[]
for t=1:T
# do nothing if stay put
if optimal_policy[i, j] == 2 # new job
j = rand(G)[1]
elseif optimal_policy[i, j] == 3 # new life
i, j = rand(F)[1], rand(G)[1]
end
push!(θ_ind, i)
push!(ϵ_ind, j)
end
return wp.θ[θ_ind], wp.ϵ[ϵ_ind]
end
fig, axes = plt[:subplots](2, 1, figsize=(10, 8))
for ax in axes
θ_path, ϵ_path = gen_path()
ax[:plot](ϵ_path, label="ϵ")
ax[:plot](θ_path, label="θ")
ax[:legend](loc="lower right")
end
```

### Exercise 2¶

The median for the original parameterization can be computed as follows

```
function gen_first_passage_time(optimal_policy::Matrix)
t = 0
i = j = 1
while true
if optimal_policy[i, j] == 1 # Stay put
return t
elseif optimal_policy[i, j] == 2 # New job
j = rand(G)[1]
else # New life
i, j = rand(F)[1], rand(G)[1]
end
t += 1
end
end
M = 25000
samples = Array{Float64}(M)
for i=1:M
samples[i] = gen_first_passage_time(optimal_policy)
end
print(median(samples))
```

```
7.0
```

To compute the median with \(\beta=0.99\) instead of the defalut value \(\beta=0.95\), replace `wp=CareerWorkerProblem()`

with `wp=CareerWorkerProblem(β=0.99)`

The medians are subject to randomness, but should be about 7 and 11 respectively. Not surprisingly, more patient workers will wait longer to settle down to their final job

```
wp2 = CareerWorkerProblem(β=0.99)
v2, optimal_policy2 = solve_wp(wp2)
samples2 = Array{Float64}(M)
for i=1:M
samples2[i] = gen_first_passage_time(optimal_policy2)
end
print(median(samples2))
```

```
14.0
```

### Exercise 3¶

Here’s the code to reproduce the original figure

```
fig, ax = plt[:subplots](figsize=(6, 6))
lvls = [0.5, 1.5, 2.5, 3.5]
ax[:contourf](tg, eg, optimal_policy', levels=lvls, cmap="winter", alpha=0.5)
ax[:contour](tg, eg, optimal_policy', colors="k", levels=lvls, linewidths=2)
ax[:set_xlabel]("θ", fontsize=14)
ax[:set_ylabel]("ϵ", fontsize=14)
ax[:text](1.8, 2.5, "new life", fontsize=14)
ax[:text](4.5, 2.5, "new job", fontsize=14, rotation="vertical")
ax[:text](4.0, 4.5, "stay put", fontsize=14)
```

Now we want to set `G_a = G_b = 100`

and generate a new figure with
these parameters.

To do this replace:

```
wp = CareerWorkerProblem()
```

with:

```
wp = CareerWorkerProblem(G_a=100.0, G_b=100.0)
```

In the new figure, you will see that the region for which the worker will stay put has grown because the distribution for \(\epsilon\) has become more concentrated around the mean, making high-paying jobs less realistic